實(shí)現(xiàn)的功能類似MySQL：
show tables;
在 PostgreSQL 中需要寫：
select * from pg_tables where schemaname = 'public';
返回結(jié)果類似如下：
schemaname | tablename | tableowner | tablespace | hasindexes | hasrules | hastriggers | rowsecurity
------------+-----------+------------+------------+------------+----------+-------------+-------------
public | deploy | postgres | | t | f | f | f
public | deploy2 | postgres | | f | f | f | f
(2 rows)
補(bǔ)充：PostgreSql 獲取所有的表、視圖、字段、 主鍵
PostgreSQL獲取數(shù)據(jù)庫中所有view名 視圖：
SELECT viewname FROM pg_views
WHERE schemaname ='public'
postgreSQL獲取數(shù)據(jù)庫中所有table名 表：
SELECT tablename FROM pg_tables
WHERE tablename NOT LIKE 'pg%'
AND tablename NOT LIKE 'sql_%'
ORDER BY tablename;
postgreSQL獲取某個表tablename 所有字段名稱 ， 類型，備注,是否為空 等
SELECT col_description(a.attrelid,a.attnum) as comment,pg_type.typname as typename,a.attname as name, a.attnotnull as notnull
FROM pg_class as c,pg_attribute as a inner join pg_type on pg_type.oid = a.atttypid
where c.relname = 'tablename' and a.attrelid = c.oid and a.attnum>0
postgreSQL獲取某個表tablename 的主鍵信息
select pg_attribute.attname as colname,pg_type.typname as typename,pg_constraint.conname as pk_name from
pg_constraint inner join pg_class
on pg_constraint.conrelid = pg_class.oid
inner join pg_attribute on pg_attribute.attrelid = pg_class.oid
and pg_attribute.attnum = pg_constraint.conkey[1]
inner join pg_type on pg_type.oid = pg_attribute.atttypid
where pg_class.relname = 'tablename'
and pg_constraint.contype='p'
以上為個人經(jīng)驗(yàn)，希望能給大家一個參考，也希望大家多多支持腳本之家。如有錯誤或未考慮完全的地方，望不吝賜教。
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